1. graph the function f(x) =x^2 +4x-12 on the coordinate plane. (a) what are the x-intercepts? (b) what is the y-intercept? (c) what is the maximum or minimum value? giving 30 points and brainliest to best

(a) x intercepts: -6 and 2

you can obtain these by solving the equation 0=x^2 +4x-12 using your favorite quadratic formula. but it is easy to verify -6 and 2 indeed satisfy this equation.

(b) y intercept: -12

this is obtained by setting x=0: 0^2+4*0-12 = -12

(c) the minimum value is: -16 (this is the vertex)

you can get the vertex by rewriting the equation into the form:

there is no global or local maximum as the function goes to infinity, so only in the limit sense: +infinity.

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step-by-step explanation: