Find the distance from p to l. line l contains points (-4,2) and (3,-5). point p has coordinates (1,2). a. 55√5 , or appx 2.2 b. 67√7 , or appx 2.3 c. 52√2 , or appx 3.5 d. 103√3 , or appx 5.8

To Find: Distance between point P to line l

Solution: Points lying on line l are suppose A (-4,2) and B (3,-5).

Equation of line passing through (p,q) and (a,b) is given by the equation

 →

Equation of line AB is ,

→

→y -2 = -1× (x +4)

→y -2 = -x -4

→x + y +4-2=0

→ x + y +2=0

Distance between point P (1,2) and line l whose equation is ,x+y+2=0 is given by= =5√2/2=3.535(approx)→Option (C)

→Which is given by the formula ,i.e if a line has equation , Ax + By +c=0 and we have to find the distance from (p,q) is given by =

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.