If the sum of five consecutive even integers is 290, what is the smallest of the five integers?

So let n be the smallest number. To have consecutive even integers each number goes up by 2 so n, n+2, n+4, n+6, n+8.

Therefore, n+n+2+n+4+n+6+n+8=290

5n+20=290

5n=270

n=54

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13