What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5? y = x – 8 y = x + 1 y = x + 1 y = x + 10

The equation of the parallel line would be y = 3/2x + 10

Step-by-step explanation:

In order to find this, we first need to find the slope of the first line. We can do this by solving for y.

2x + 3y = -5

3y = -2x - 5

y = -2/3x - 5/3

Now we know the slope to be 3/2 since perpendicular lines have the opposite and reciprocal. So we can use point-slope form to find the equation of the line.

y - y1 = m(x - x1)

y - 1 = 3/2(x - -6)

y - 1 = 3/2x + 9

y = 3/2x + 10

While this doesn't match any of your options, it is correct for the given parameters.

The correct answewr choice is y = 3/2x + 10 (D)

Step-by-step explanation:

I just took the Algebra quiz.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

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step-by-step explanation: