If you wanted to make the graph of y=5x+3 les steep, which equation could you use?

B

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = 5x + 3 is in this form with slope m = 5

To decrease the slope we require a smaller, positive value for m

y = x + 3 has m = 1 which is less than 5 and positive

y = x + 3 is less steep than y = 5x + 3

the answer is c. 23/3

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.