One factor of f(x)= 5x^3+ 5x^2- 170x+ 280 is (x + 7). what are all the roots of the function? use the remainder theorem. x = –4, x = –2, or x = 7 x = –7, x = 2, or x = 4 x = –7, x = 5, or x = 280 x = –280, x = –5, or x =

The roots are x = -7, 2 and 4.

Step-by-step explanation:

5x^3+ 5x^2- 170x+ 280  divided by x + 7

= 5x^2 - 30x  + 40

= 5(x^2 - 6x + 8) = 0

5(x - 4)(x - 2) = 0

x  = 2, 4

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step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x