Tentukan persamaan garis yang di wakili ruas garis ab, bc, cd dan ad! tolong kak

Answers:

1. AB: y = - 2x - 6

2. BC: y = x - 3

3. CD: x = 3

4. AD: y = (3/7) x +26/7

Solution:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

1. AB

A=(-4,2)=(xa, ya)→xa=-4, ya=2

B=(-1,-4)=(xb, yb)→xb=-1, yb=-4

mab=(yb-ya)/(xb-xa)

mab=(-4-2)/(-1-(-4))

mab=(-6)/(-1+4)

mab=(-6)/(3)

mab=-2

y-ya=mab (x-xa)

y-2=-2(x-(-4))

y-2=-2(x+4)

y-2=-2x-8

y-2+2=-2x-8+2

y=-2x-6

2. BC

B=(-1,-4)=(xb, yb)→xb=-1, yb=-4

C=(3,0)=(xc, yc)→xc=3, yc=0

mbc=(yc-yb)/(xc-xb)

mbc=(0-(-4))/(3-(-1))

mbc=(0+4)/(3+1)

mbc=(4)/(4)

mbc=1

y-yc=mbc (x-xc)

y-0=1 (x-3)

y=x-3

3. CD

C=(3,0)=(xc, yc)→xc=3, yc=0

D=(3,5)=(xd, yd)→xd=3, yd=5

mcd=(yd-yc)/(xd-xc)

mcd=(-4-0)/(3-3)

mcd=(-4)/(0)

mcd= Infinite (Vertical line)

Equation vertical line: x=xc=xd

x=3

4. AD

A=(-4,2)=(xa, ya)→xa=-4, ya=2

D=(3,5)=(xd, yd)→xd=3, yd=5

mad=(yd-ya)/(xd-xa)

mad=(5-2)/(3-(-4))

mad=(3)/(3+4)

mad=3/7

y-ya=mad (x-xa)

y-2=(3/7)(x-(-4))

y-2=(3/7)(x+4)

y-2=(3/7)x+12/7

y-2+2=(3/7)x+12/7+2

y=(3/7)x+(12+7(2))/7

y=(3/7)x+(12+14)/7

y=(3/7)x+26/7

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

.25

step-by-step explanation: