G(p)=(p-2 )and g(x)=(p^3+4p^2-2) evaluate g(p)*h(p) by modeling or by using the distributive property.

Given that g(p)=p-2 and

Now we have to evaluate g(p)*h(p) by modeling or by using the distributive property.

We know that g(p)*h(p) means just multiply expressions of g(p) with h(p)

which can be shown as following:

Apply distributive property

Hence final answer is

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

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