F(x) = x + 7 and g(x) = x - 2, i honestly have no clue where to start im confused

A) {x | x ≠ 2}

Step-by-step explanation:

Domain is: all the values that x can be. Look for the following restrictions:

denominator (bottom) cannot be zero (set denomiantor ≠ zero)square root cannot be negative (set inside of square root ≥ 0)logs must be positive (set log > 0)

denominator is: x - 2 so set it unequal to zero and solve.

x - 2 ≠ 0

  +2   +2

x     ≠  2

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.