How to find three consecutive integers whose sum is 336?

There's a quick, easy, sloppy way, and there's a good math way.
Here's the good math way:

If the integers are consecutive, then you can call them  'x',  (x+1), and  (x+2).

We know what their sum is, so let's add them up:

x + (x+1) + (x+2)  =  336

x +  x+1  +  x+2    =  336

Combine the terms that are alike on the left side:

                                           3x + 3  =  336

Subtract 3 from each side:    3x = 333

Divide each side by 3 :              x = 111

The integers are  111,  112,  and 113 .

The right answer should be 6 but your not very specific