Correct answer only ! i cannot retake newton’s law of cooling states that for a cooling substance with initial temperature t^0 , the temperature t(t) after t minutes can be modeled by the equation t(t) = t^s+(t^0−t^s)^e−kt , where t^s is the surrounding temperature and k is the substance’s cooling rate. a liquid substance is heated to 80°c . upon being removed from the heat, it cools to 60°c in 15 min. what is the substance’s cooling rate when the surrounding air temperature is 50°c ? round the answer to four decimal places. a. 0.0687 b. 0.0732 c. 0.0813 d. 0.0872