Trisha has a game board as shown below, which is a square that has a total area of 400 square inches. the area of the large circle is 314 square inches. what is the probability that trisha will not get any points with one randomly thrown dart that lands somewhere inside the square? round decimals to two decimal places. 0.22 0.25 0.79 0.82

First option is correct.

Step-by-step explanation:

Since we have given that

Total area of square inches = 400

The area of the large circle = 314

Now, we need to find the probability that Trisha will not get any points with one randomly thrown dart that lands somewhere inside the square,

Let E be the event the Trisha will get points .

so,

As we know that

So, Probability that Trisha will not get any points with one randomly thrown dart that lands somewhere inside the square = 0.22

So, First option is correct.

18a

step-by-step explanation:

simply because it is. it's the highest common factor

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841