Brainliest answer plus extra points!how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 80% antifreeze? use the six-step method.

.7X+.25*100=.6(100+X)

.7X+25=60+.6X

.7X-.6X=60-25

.1X=35

X=35/.1

X=350 GALLONS OF 70% ANTIFREEZE WILL BE NEEDED.

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !