Guys i needa submit this asap pls omg : '(( 2. draw the image of ∆rst under the dilation with scale factor 5/3 and center of dilation (2, 2) − . label the image ∆r′s′ t′. show your work.

Given coordinates of the triangle RST are R(2,1), S(2,-2) and T(-1,-1).

Center of center of dilation is (2,-2).

Because center of dilation is (2,-2) so the coordinates of dilated image S(2,-2) would stay same.

Now, we need to apply rule for dilation with the scale factor 5/3.

Each of R(2,1), and T(-1,-1) would be and R' and T' would be in ratio 5/3.

We will extend RS to 5 units and TS also 5 units.

The new resulting image would be dilated triangle by a scale factor 5/3.

New coordinates would be

R'(2,3), S'(2,-2) and T'(-3,-2)

damm bro the struggle

step-by-step explanation:

this is answer of 144 cubic meters