How long is the arc intersected by a central angle of pi/3 radians in a circle with a radius of 6 ft? round your answer to the nearest tenth. use 3.14 for pi 1.0 ft 5.7 ft 6.3 ft 7.0 ft

6.3 ft

Step-by-step explanation:

We are given,

the central angle of the arc = radians; and

radius of the arc = 6ft

Therefore using these values, we can find the length of the long arc.

Length of the arc = 6 × / 3

Lenth of the arc = = 2 × 3.14 = 6.28

Therefore, the length of the arc, rounded to the nearest tenth is 6.3 ft.

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !