Divide x^3 -3x^2 by x-2 . step 1 - fill in the missing number:

Step-by-step explanation:

First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items

F(x) = x^3-3x^2+0x+0

We have to divide this by x-2

Leading terms in the dividend and divisor are

x^3  and x

Hence quotient I term would be x^3/x=x^2

                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

Multiply x-2 by x square and write below the term and subtract

We get  

                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

-x^2+0x

Again take the leading terms and find quotient is –x

                                                x-2) x^3-3x^2+0x+0(x^2-x

x^3-2x^2

-x^2+0x

                                                                  -x^2-2x

Subtract to get 2x +0 as remainder.

                                                  x-2) x^3-3x^2+0x+0(x^2-x-2

x^3-2x^2

-x^2+0x

                                                                  -x^2+2x

                                                                      -2x-0

                                                                              -2x+4

                                                                               -4

Thus remainder is -4 and quotient is x^2-x-2

$9.41

step-by-step explanation: