Write an equation for the graph of the line that passes through the point (3,2) and is perpendicular to the line x-2y=-6

The equation of the line would be y = -2x + 8

Step-by-step explanation:

In order to find this, we first need to find the slope of the original equation. We can do this by solving for y.

x - 2y = -6

-2y = -x - 6

y = 1/2x + 3

Now that we have a slope of 1/2, we know the new perpendicular line will have a slope of -2. We know this because perpendicular lines have opposite and reciprocal slopes. This means we flip it and change the sign. Now we can use this slope along with the point to find the equation.

y - y1 = m(x - x1)

y - 2 = -2(x - 3)

y - 2 = -2x + 6

y = -2x + 8

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

none cuz there are no "following statements" regarding the question

step-by-step explanation: