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![a=6,\ b=5\\\\\log_3(9ab^2)=\log_3[(9)(6)(5^2)]=\log_39+\log_36+\log_35^2\\\\=\log_33^2+\log_3(3\cdot2)+2\log_35=2\log_33+\log_33+\log_32+2\log_35\\\\=2+1+\log_32+2\log_35=3+\log_32+2\log_35](/tpl/images/0051/0828/03145.png)
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If a=6 and b=5, find the answer to log base 3 (9ab^2)...
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