Look at the figure shown below: rq is a segment on which a perpendicular bisector ps is drawn. s is the midpoint of rq. which step should be used to prove that point p is equidistant from points r and q?

These are the steps, with their explanations and conclusions:

1) Draw two triangles: ΔRSP and ΔQSP.

2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).

3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.

4) The segment SP is common to both ΔRSP and Δ QSP.

5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.

Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.