75 points 1. write a rule for the sequence. 8, -1, -10, - a. start with 8 and add -9 repeatedly b. star with -9 and add 8 repeatedly c. start with 8 and add 9 repeatedly d. start with 8 and subtract -9 2. find the next three terms of the sequence. -6, -24, -96, -384 1) -768, -1536 , -3072 2) -768, -3072, -12288 3) -1536, -6144 , -24567 4) -1536, -9216, -36864 if you can with the whole test that would be !

Hi Timothy,

1. Write a rule for the sequence.

8, -1, -10, -19...

A. Start with 8 and add -9 repeatedly

B. star with -9 and add 8 repeatedly

C. start with 8 and add 9 repeatedly

D. start with 8 and subtract -9 repeatedly---

Answer - So you have to start with -9 then keep subtracting 9. Thats what I think the answer is but the answer is not stated in the question. Let me know on what that is. The closest answer is probably either B or D.

2. find the next three terms of the sequence.

-6, -24, -96, -384

1) -768, -1536 , -3072

2) -768, -3072, -12288

3) -1536, -6144 , -24567

4) -1536, -9216, -36864

The rule is multiplying by 4!

So the correct answer is 3) -1536, -6144 , -24567

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

dwe

step-by-step explanation:

ewd