How would the fraction 1/3+square root of 2 be rewritten if its denominator is rationalized using difference of squares? a. 3-square root of 2 b. 3-square root of 2/5 c. 3-square root of 2/7 d. - 3+square root of 2/7

C

given 1 /( 3 + √2 )

then rationalise the denominator by multiplying the numerator/ denominator by the conjugate of the denominator

the conjugate of 3 + √2 is 3 - √2

1 / (3 + √2 ) × (3 - √2 ) / (3 - √2 )

= (3 - √2 ) /( 9 - 2 ) = (3 - √2 ) / 7

is correct

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