What are the dimensions of a rectangle whose length is 4 more than twice the with and whose perimeter is 3 less than 7 times the width

w =width

l = 2w+4

p= 7w-3

P = 2(l+w)

substitute in p = 7w-3 and l = 2w+4

7w-3 = 2(2w+4+w)

combine like terms

7w-3 =2(3w+4)

distribute

7w-3 = 6w +8

subtract 6w from each side

w-3 = 8

add 3 to each side

w = 11

l = 2w + 4

l = 2(11) + 4 = 22+4 = 26

P = 7w-3 = 7*11-3 = 77-3 = 74

360/29

step-by-step explanation:

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.