Two airplanes leave an airport at the same time and travel opposite directions. one plane travels 81 km/h slower than the other. if the two planes are 6140 km apart after 4 hours, what is the rate of each plane?

The speed of the faster plane is 899 km/hr

The speed of the slower plane is 824 km/hr

Step-by-step explanation:

Equation for faster plane:

(1) +d+=+s%2A4+

Equation for slower plane:

(2) +6892+-+d+=+%28+s+-+75+%29%2A4+

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8