Brainliest answer ! a cashier has a total of 98 bills, made up of fives and fifties. the total value of the money is $2425. how much of each kind does he have?

84 5$ bills and 42 $10 bills

Step-by-step explanation:

The problem has two variables, let:

   F=number of $5 bills

   T=number of $10 bills

Translate:

 "a total of 126 bills, made up of fives and tens"   means

                  126           =             F     +    T                        (the number of each)

 "total value of the money is $800"     means  

            5F + 10T              = 800                  [use $10 and $5 times the number of bills]

Now, solve for either T or F in the first equation and put that into the second equation:

         T = 126 - F

          5F + 10(126-F) = 800                [now, all expressed in terms of F so we can solve for F]

           5F + 1260 -10F = 800             [distribute]

           -5F = -460                            [subtract 1260 from both sides]

            F = 92                                [divide both sides by -1]

Now, put that value into either of the equations to solve for T (the second equation looks easy):

            T = 126 - F

            T = 126 - 92

            T = 34

Checking (very important):

 Is   126 = 92 + 34  ?

        126 = 126  ? yes

 Is   5(92) + 10(34) = 800  ?

        460  +  340  = 800   ?

              800  =  800  ? yes

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

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