Bsegments ab , cd , and ef intersect at point o, points a, e, c and points b, f, d are collinear so that ao ≅ ob , co ≅ od . prove that ae ≅ bf

Given

Segments  AB,  CD ,and  EF  intersect at point O.

points A, E, C and points B, F, D are collinear

AO  ≅  OB

,  CO  ≅  OD

Prove that

AE  ≅   BF

To proof

As given in the question

points A, E, C and points B, F, D are collinear

Collinear points

These are the points lie in the single striaght line.

this shows points A, E, C and points B, F, D are lie in the single striaght line.

As given in the question

AO  ≅  OB  ,   CO  ≅  OD  

In ΔAOC and ΔBOD

AO  ≅  OB

∠AOC = ∠ BOD  ( Vertically opposite angle )

CO  ≅  OD

ΔAOC ≅ Δ BOD

By using the SAS congurence property

∠CAO = ∠OBD

( By corresponding sides of the congurent triangle )

In ΔAOE and Δ BOF

∠OAE = ∠OBF ( As proof above )

AO = OB

∠AOE = ∠BOF  ( Vertically opposite angle )

ΔAOE  =Δ BOF

By using the ASA congurence property

AE  ≅  BF

( By corresponding sides of the congurent triangle )

Hence proved

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*