Determine wether each ordered pair is a solution of the given equation. 17. y=3x-5; (0,5), (-1,-8) 18. y=-2x+7; (1,,3) 19. -6x+5y=-6; (1,0), (2,6/5) 20. 5x-3y=9; (0,3), (12/5,-1) 21. y=2x^2; (1,2), (3,18) 22. y=2|x|; (-1,2), (0,2) 23. y=^3; (2,8), (3,9) 24. y=x^4; (-1,1), (2,16) 25. y=√x+2; (1,3), (4,4) 26. y=3√x-4; (1,-3), (8,6)

no not all of them.

step-by-step explanation:

some of them have a square base.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source