The first floor of the house consists of a kitchen, playroom, and dinning room. the areas of the kitchen, playroom, and dinning room are in the ratio 4: 3: 2.the combined area of these three rooms is 189 square feet. what is the area of each room?

The area of the kitchen, playroom, and the dining room floor are 84ft², 63ft² and 42ft² respectively

The area of each floor will be:

Kitchen = 4/9 × 189ft² = 84ft²

Playroom = 3/9 × 189ft² = 63ft²

Dinning room = 2/9 × 189ft² = 42ft²

Therefore, the area of the kitchen, playroom and the dining room floor are 84ft², 63ft², and 42ft² respectively.

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4 : 3 : 2

x - area unit

area of the kitchen = 4x

area of the playroom = 3x

area of the dinning room = 2x

The combined area of these three rooms is 189 ft².

Therefore we have the equation

4x + 3x + 2x = 189

9x = 189    |:9

x = 21 ft²

area of the kitchen = 4x = 4(21) = 84 ft²

area of the playroom = 3x = 3(21) = 63 ft²

area of the dinning room = 2x = 2(21) = 42 ft²

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.