The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. the average weight of one pig is 95 pounds 10 ounces. find the following: a. the net weight of the pigs in the truck. b. the weight of the empty truck.

Gross weight of the truck with 30 pigs = 8 tons, 1123 pounds and 6 ounces

= (8 × 2000 × 16) + (1123 × 16) + 6 ounces

= 256000 + 17968 + 6

= 273974 ounces

The average weight of one pig = 95 pounds 10 ounces

= (95 × 16) + 10 ounces

= 1520 + 10 = 1530 ounces

a.  Net weight of the pigs in the truck = 30 × 1530 = 45900 ounces

= 2868 pounds 12 ounces

= 1 ton 868 pounds and 12 ounces

b. Weight of the empty truck = Gross weight of the truck containing 30 pigs - Net weight of the pigs in the truck

= 273974 - 45900

= 228074 ounces

= 14254 pounds 10 ounces

= 7 tons 254 pounds and 10 ounces

d

step-by-step explanation:

answer: 33 ( approx)

step-by-step explanation:

since, in the linear regression formula, the slope is the a in the equation y = b + ax ( by comparing it with the general equation of line y = mx + c )

where,

here given table is,

price ($), x   :           18         23       25       29       30       33

pairs sold, y :         16         13         10       8         6       2

so, ,   ,   ,

and   ,

thus, slop of the given line is,

⇒  

⇒   ≈ 33