40 points to who ever can answer ! which quadratic function does the graph represent? the vertex is at (-2,-3) and the point is at (0,7) a.)f(x)=5/2(x+2)^2-3 b.) f(x)= 10/9(x+2)^2-3 c.) f(x)=7(x-2)^2-3 d.)f(x)=5(x-2)^2-3

y = 2.5(x + 2)^2 - 3

The answer is A

Step-by-step explanation:

The general equation for the vertex is

y  =  a (x + b)^2 + c

a we are not certain about

b = 2

c = - 3

y = a(x + 2)^2 - 3 Now we have to solve for a.

a is found by using the one point we know (0,7) It means when x = 0 y = 7 so just put those two numbers in.

7 = a(0 - 2)^2 - 3

7 = a (- 2)^2 - 3       Add 3 to both sides.

7 + 3 = a(4)              Combine 7 and 3

10 = 4a                     Divide by 4

10/4 = a                    Do the actual division    

2.5 = a

See above

A

the equation of a parabola in vertex form is

y = a(x - h )² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

here the vertex = (- 2, - 3 ), thus

y = a(x + 2 )² - 3

to find a substitute (0, 7 ) into the equation

7 = 4a - 3 ( add 3 to both sides )

10 = 4a ( divide both sides by 4 )

a = =

y = (x + 2 )² - 3

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.