What are the solutions of the following system? { 10x^2-y=48 and 2y=16x^2+48 a) (2 sqrt3, 120) and (-2 sqrt3, 120) b) (2 sqrt3, 120) and (-2 sqrt 3, -72) c) (6, 312) and (-6, 312) d) (6, 312) and (-6,-264)

C

Step-by-step explanation:

we are given

Firstly, we will solve for y

now, we can plug that into first equation

now, we can simplify it

Add both sides by 24

Divide both sides by 2

now, we can solve for x

now, we can find y-value

At x=-6:

we can plug x=-6

At x=6:

we can plug x=6

so, we get solution as

C) (6, 312) and (-6, 312)..........Answer

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.