Find the first, fourth, and eighth terms of the sequence. a(n)=-2 x 2^n-1

2, 16 and 256.

Step-by-step explanation:

Just substitute  for n:-

first term ( when n = 1) =  2 * 2^(1-1)

= 2 * 1 =  2

4th term =  2 * 2^(4-1) =  16

8th term = 2* 2^(8-1) = 256

28

step-by-step explanation:

because that's the answer

my guess would be b and d, but i didn’t actually get out the pen and paper. lol