If m^2 + n^2 = 18 and mn=7, what is (m-n)^2

(m-n)^2 = m^2 - 2mn + n^2

(m-n)^2  = m^2 + n^2 - 2mn

Substitute m^2 + n^2 = 18 and mn=7

(m-n)^2 =18 - 2(7)

(m-n)^2 = 18 - 14

(m-n)^2  = 4

(m - n)^2 = 4

Step-by-step explanation:

(m - n) ^2 = m^2 - 2mn + n^2 when (m-n)^2 is expanded using foil.

But m^2 + n^2 = 18         Given

mn = 7                             Given

(m - n)^2  = m^2 + n^2 - 2 mn  Substitute in the given values

(m -  n)^2= 18 - 2*7           Reduce

(m - n)^2 = 18 - 14             Combine

(m - n)^2 =  4                

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

it's d

step-by-step explanation: