Sam packed 42 kg of rice into one big bag and six small ones which were of the same size the small bags .each contain 1/10 of the rice .how many kilograms of rice did the big bag contain?

we are given

Sam packed 42 kg of rice

So, total amount of rice =42kg

And there are six small bags

each contains 1/10 of the rice

So, rice on each bags is

kg

so, total rice in 6 bags is

kg

kg

so, the rice in big bag = ( total amount of rice )-( total rice in six small bags)

we can plug values

and we get

so, the rice in big bag is

kg..............Answer

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: 0.64

step-by-step explanation: