An arithmetic series consists of consecutive integers that are multiples are of 4. what is the sum of the first nine terms of this sequence if the first term is 0

144

Step-by-step explanation:

If the first term is 0, the second is 4, the third 16, and so on.  The appropriate formula for this is a(n) = 4*(n-1).  The ninth term is a(9) = 4*(8) = 32

This partial series looks like {0, 4, 8, 12, 16, 20, 24, 28, 32 }

The sum of these nine terms is equal to 9 times {the sum of the 1st and last terms}, divided by 2, or 9(0+32)/2, or 9(16), or 144.

2/3

step-by-step explanation: