Atruck carrying automobiles is approaching a bridge that can support a maximum weight of 45,000 pounds. there are 7 automobiles on the truck. if each automobile weighs 3,500 pounds, what is the most that the truck itself can weigh in order to cross the bridge safely? 20,500 pounds 41,493 pounds 41,500 pounds 69,500 pounds

Number of automobiles on the truck = 7

Weight of each automobile = 3500 pounds

Hence, weight of 7 automobiles is =  

As given, the bridge that can support a maximum weight of = 45000 pounds

So, the truck should weigh = pounds

Hence, the truck itself can weigh 20,500 pounds in order to cross the bridge safely.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

20

step-by-step explanation: