In δpqr shown below, segment qs is an altitude: triangle pqr with segment sq drawn from vertex q and intersecting side rp. which of the following is a justification used while proving the similarity of triangles δpsq and δqsr? a. transitive property of equality b. addition property of equality c. definition of an altitude d. definition of supplementary angles

c. Definition of altitude.

Step-by-step explanation:

We are given that segment QS is an altitude in ΔPQR and we are asked to find a justification used while proving the similarity of triangles ΔPSQ and ΔQSR.

Since we know that altitude meets opposite side at right angles. When QS will intersect line PR we will get two right triangles QSR and QSP right angled at S.

ΔPQR is similar to ΔPSQ as they both share angle P and right triangle. So their third angle should also be similar.

ΔPQR is similar to ΔQSR as they both share angle R and both have a right triangle at Q and S respectively. So they will have their third angle equal.

ΔPQR is similar to triangles ΔQSR and ΔPSQ. Therefore, ΔQSR is similar to ΔPSQ.

Therefore, by definition of altitude triangles ΔPSQ and ΔQSR are similar as ΔPSQ and ΔQSR are created from ΔPQR by altitude QS.

for this case we have the following expression:

to solve, we rewrite the expression as:

we apply double c and we have:

thus, the quotient is 48.

so, patel found a wrong ratio and the multiplication was incorrect.

option d

step-by-step explanation:

this is not a question