What is the solution set of the equation using the quadratic formula? x2+6x+10=0 {−3+i, −3−i} {−3+2i, −3−2i} {−6+2i, −6−2i} {−2i, −4i} jamal solved the equation by completing the square. x2−8x+14=0 which equation shows one of the steps jamal could have taken to complete the square? x2−8x+16=−14+16 x2−8x+64=−14+64 x2−8x+16=−14 x2−8x+64=−14

(1)

we are given

we can use quadratic formula

now, we can compare and find a , b and c

we get

now, we can plug these values into quadratic formula

we can simplify it

so, we will get solution

{−3+i, −3−i}.........Answer

(2)

we are given equation as

Since, Jamal solve this equation by completing square

so, firstly we will move constant term on right side

so,  subtract both sides by 14

we can write

so, we will add both sides by 4^2

we get

..............Answer

do you have an easier question cause this shh is hard like theheck

step-by-step explanation:

2, 2, 2 or -4, 20, 29

step-by-step explanation:

there is two ways you can do it.