What are the like terms in the algebraic expression? −x2y + 2xy2 − 5 + 3y − 4xy + y june claims the like terms are: 3y and y −x2y and 2xy2 did june identify the correct like terms? check the correct statement.

No, June did not identify the correct like terms.

Step-by-step explanation:

The given algebraic expression is

In an algebraic expression, two terms are called like terms if they have the same variables and powers.

In the given algebraic expression 3y and y are like terms because both terms have the same variable y with power 1.

In the given algebraic expression -x²y and 2xy² are not like terms because both terms have the same variables x and y but having different powers.

June claims the like terms are: 3y and y ,-x²y and 2xy/

Since 3y and y are like terms and -x²y and 2xy² are not like terms, therefore June did not identify the correct like terms.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°