Apicture has a height that is 4/3 its width. it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement?

height(h) = 4/3 x

width(w) = x

(hw) = 192, but to substitute

(4/3 x)(x) = 4/3 x^2

Since 4/3 x^2 = 192, the reciprocal is used to isolate x, so multiply 3/4 on both sides

3/4 x 4/3 x^2 = 192 x 3/4

x^2  = 144

x = 12

height = 4/3(12) = 16

width = 12

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )