The rays om , on , and op in the figure, coincide at time t=0. at the same instant of time om and op rotate in the plane about point o in opposite directions while on remains fixed. with respect to on , segment om rotates at constant rate of 3° per second and op , at 6° per second. what is the smallest positive value of t, in seconds, for which segments om and op will coincide?

Note:

Note that the shape is a circle(s), as they all will rotate until they coincide. However, they are rotating towards each other

Step-by-step explanation:

One is rotating at 3°, while the other is rotating at 6°. We do not need to both with ON, for the question is not asking for that segment.

A circle has 360° To solve this, we must know that "the other" must complete a circle and overtake the other one.

So. First, solve for the circle (360°)

360/6 = 60

It takes one of the rays to rotate a full circle 60 seconds.

The other, at the same time, has rotated half way, as:

360/3 = 120

Remember that one of the rays (the one that is faster), completes it's turn twice as fast. This means that you must solve for the mean:

(60 + 120)/2 = 180/2 = 90

90 seconds will be used until one overtakes the other

~Senpai

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

i think asking google will you get the answer to that question