Mathematics, 05.07.2019 22:30 msjbryant33
Write an equation of the line that passes through (β3,3) and is perpendicular to the line 2y=8xβ6.
Answers: 2
![\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em}slope = m\implies -\cfrac{1}{4}\\\\\\ \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}\implies y-3=-\cfrac{1}{4}[x-(-3)]\implies y-3=-\cfrac{1}{4}(x+3)\\\\\\y-3=-\cfrac{1}{4}x-\cfrac{3}{4}\implies y=-\cfrac{1}{4}x-\cfrac{3}{4}+3\implies y=-\cfrac{1}{4}x+\cfrac{9}{4}](/tpl/images/0055/6296/788a1.png)
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Write an equation of the line that passes through (β3,3) and is perpendicular to the line 2y=8xβ6....
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