For a set of 3 consecutive odd intergers, 3times the largest interger is 7 less than twice the sum of the other 2 intergers. what is the largest interger in the set

For a set of 3 consecutive odd integers,

n, (n+2), (n+4)

3 times the largest integer is 7 less than twice the sum of the other 2 integers.

3(n+4) = 2(n + n+2) - 7

3n + 12 = 2(2n + 2) - 7

3n + 12 = 4n + 4 - 7

3n + 12 = 4n - 3

12 + 3 = 4n - 3n

15 = n is the 1st integer

:

What is the largest integer in the set  

15 + 4 = 19 is the largest integer

:

:

See if that checks out in the statement

"3 times the largest integer is 7 less than twice the sum of the other 2 integers. "

3(19) = 2(15 + 17) - 7

57 = 2(32) - 7

mark brailiest

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i