What is the equation of a line, in point-slope form, that passes through (5, -3) and has a slope of 2/3?

y+3 = (2/3)(x -5)

Step-by-step explanation:

The point-slope form is ...

... y - k = m(x -h) . . . . . for slope m, point (h, k)

You have m = (2/3), h = 5, k = -3. Putting these numbers into the formula gives ...

... y -(-3) = (2/3)(x - 5)

... y + 3 = (2/3)(x - 5) . . . . . . matches the last selection

h/o/e/s mad

step-by-step explanation:

si si si