Arestaurant sells 330 sandwiches each day. for each $0.25 decrease in price, the restaurant sells about 15 more sandwiches. how much should the restaurant charge to maximize daily revenue? what is the maximum daily revenue? each sandwich is $6

The maximum daily revenue is with 1 decrease in price.

Step-by-step explanation:

Let x be the number of $0.25 decreases in price and R to be the daily revenue in dollar.

Since,

R(x)=

=

= 1980+7.5x-3.75x^2

∴       ....(1)

For a quadratic equation in standard form , the axis of symmetry is a vertical line

Here, a= -3.75 b=7.5

then,

Substitute the value of x=1 in equation (1), to find the maximum revenue;

=

Therefore, the maximum daily revenue is, with x=1 decrease in price.

207/8 is the right

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step-by-step explanation: