The first one asks for the value of x. i need on both. i am struggling to understand how to do this,

(1) since the horizontal lines are parallel, and you know the vertical intersecting line crosses at right angle, it must be that the two angles with variable x sum up to 90 degrees. So same rewritten as an equation:

x+8+6x-58 = 90

7x = 140

x = 20 (degrees)

(2) here you have two variable so you will need to find two equations.

The first one comes from the triangle and its angles summing up to 180:

63 + (3x+45) + (y-6) = 180

The second one comes from the fact that the two horizontal lines are parallel and so the angles (7x-7) and (3x+45) must be the same:

7x-7=3x+45

Let's solve the last one first:

4x = 52

x = 13

then plug this solution into the first equation and solve for y

63 + (3x+45) + (y-6) = 180

3x + y = 78

y = 78-39 = 39

so the value of y is 39 (degrees)

x = 25/2304

step-by-step explanation:

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.