Answer these i need ! 1-5 questions.1: what is the range of the data set? 27, 5, 11, 13, 10, 8, 14, 18, 7a. 22b. 7.5c. 11d. 162. use the list below to find the lower quartile.27, 5, 11, 13, 8, 14, 18, 7a. 7b. 7.5c. 8d. 8.53. use the list below to find the upper quartile.27, 5, 11, 13, 10, 8, 14, 18, 7a. 11b. 13c. 14d. 164. what is the interquartile range of this data set? 5, 5, 6, 7, 9, 11, 14, 17, 21, 23a. 7b. 9c. 11d. 135. what is the interquartile range of this data set? 4, 5, 7, 9, 10, 14, 16, 24a. 6b. 7c. 8d. 9 !

1.  22

2.  7.5

3. 16

4. 11

5. 8.5

Step-by-step explanation:

1) Given data set : 27, 5, 11, 13, 10, 8, 14, 18, 7

To find : Range

Solution :

Range refers to the  difference between the largest and smallest term in a given data set.

Here,

largest term = 27

smallest term = 5

Therefore, Range = 27 - 5 = 22

2) In increasing order, we can write this data as 5, 7, 8, 11, 13, 14, 18, 27

The lower quartile, denoted by is the value of median of the lower half of a data set .

Now, the lower half of the data is, {5, 7, 8, 11}, so  the lower quartile is the median of {5, 7, 8, 11} .

As number of terms in lower half of the data is even, median is the mean of middle values i.e,

3)

The upper quartile denoted by is the median of the upper half of a data set.

Now, the upper half of the data is, {5, 7, 8, 11} , so the upper quartile is the median of {13, 14, 18, 27}

As the number of terms is even, upper quartile is the mean of middle values

i.e,

4) Given data : 5, 5, 6, 7, 9, 11, 14, 17, 21, 23

First half set = 5, 5, 6, 7, 9

Second half set = 11, 14, 17, 21, 23

We know that interquartile range = = 17 - 6 = 11

5) Given data : 4, 5, 7, 9, 10, 14, 16, 24

lower half of the data : 4, 5, 7, 9

upper half of the data : 10, 14, 15, 24

Therefore, interquartile range =