Mathematics, 06.07.2019 02:00 mary9590
Solve for each system of equation (any on this topic is greatly appreciated)
Answers: 2
![\bf \begin{cases}5x-2y=4\\2x-y=1\end{cases}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\stackrel{\textit{solving the 2nd equation for \underline{y}}}{2x-y=1\implies 2x-1=\boxed{y}}~\hspace{5em}\stackrel{\textit{substituting the found \underline{y} in the 1st equation}}{5x-2\left( \boxed{2x-1} \right)=4}\\\\\\5x-4x+2=4\implies x=4-2\implies \blacktriangleright x = 2\blacktriangleleft](/tpl/images/0056/2071/ff2df.png)
![\bf \stackrel{\textit{now, we substitute the found \underline{x} in the 1st equation}}{5(2)-2y=4\implies 10-2y=4}\implies 10-4=2y\\\\\\6=2y\implies \cfrac{6}{2}=y\implies \blacktriangleright 3=y \blacktriangleleft\\\\[-0.35em]\rule{34em}{0.25pt}\\\\~\hfill (2,3)~\hfill](/tpl/images/0056/2071/450f6.png)
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Solve for each system of equation (any on this topic is greatly appreciated)[tex]\left \{ {{5x-2y=4...
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