Asalvage ship’s sonar locates wreckage at a 12 degree angle of depression. a diver is lowered 40 meters to the ocean floor. how far does the diver need to walk along the ocean floor to the wreckage? 188.2 units 8.5 m 192.4 m 41.0 m

The diver need to walk 188.2m along the ocean floor to the wreckage.

Step-by-step explanation:

Check the attachment for diagram.

Using SOH, CAH TOA to get the distance the diver need to walk along the ocean floor to the wreckage,

Note that the angle is a right angled triangle with the height of the triangle being the opposite side and the distance needed as the adjacent side.

Using TOA

Tan(theta) = Opposite/Adjacent

Given theta = 12°

Opposite = 40m

Adjacent side = x

Tan12° = 40/x

x = 40/tan12°

x = 188.2m

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

i got 10.28 but that rounds up to 10.3