Which shows the equation below written in the form ax2+bx+c=0 2x2-3=-6x-2

Given equation : .

We need to write it in standard form

First we need to get rid -2 from right side.

Adding 2 on both sides we get

Now, we need to get rid -6x from right side to get 0 on rigth side.

Adding 6x on both sides we get

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

answer: i guess 5 units?

step-by-step explanation: