What is the zeros and graph of f(x)=1/2(x+5)(x+1)(x-2)

When you write a polynomial in the form

You know that you have a polynomial of degree , which crosses the x axis at

So, in your case, you have a cubic which crosses the x axis at x=-5, x=-1 and x=2.

Moreover, since A=1/2 is positive, the end behaviour of the cubic is preserved, i.e.

This is all the information you need to sketch a first draft of the graph.

y=mx+b is the final answer!   : )

the forst and 3rd

step-by-step explanation: